Problem: Optimally pack n unit circles into the smallest possible equilateral triangle.

Let L(n) denote the length of the side of the smallest equilateral triangle in which n circles have been packed optimally. This number is, in general, unknown.
Problem: Optimally pack n unit circles into the smallest possible equilateral triangle.

Let L(n) denote the length of the side of the smallest equilateral triangle in which n circles have been packed optimally. This number is, in general, unknown.
Suppose n teams play each other, and let Team Team
Team
denote some fixed ranking (where
is some permutation of
). An upset occurs when a lower ranked team beats an upper ranked team. For each ranking,
, let
denote the total number of upsets. The minimum upset problem is to find an “efficient” construction of a ranking for which
is as small as possible.
In general, let denote the number of times Team i beat team $j$ minus the number of times Team j beat Team i. We regard this matrix as the signed adjacency matrix of a digraph
. Our goal is to find a Hamiltonian (undirected) path through the vertices of
which goes the “wrong way” on as few edges as possible.
Use this sagemath/python code to compute such a Hamiltonian path.
def hamiltonian_paths(Gamma, signed_adjacency_matrix = []):
"""
Returns a list of hamiltonian paths (spanning trees of
max degree <=2).
EXAMPLES:
sage: Gamma = graphs.GridGraph([3,3])
sage: HP = hamiltonian_paths(Gamma)
sage: len(HP)
20
sage: A = matrix(QQ,[
[0 , -1 , 1 , -1 , -1 , -1 ],
[1, 0 , -1, 1, 1, -1 ],
[-1 , 1 , 0 , 1 , 1 , -1 ],
[1 , -1 , -1, 0 , -1 , -1 ],
[1 , - 1 , - 1 , 1 , 0 , - 1 ],
[1 , 1 , 1 , 1 , 1 , 0 ]
])
sage: Gamma = Graph(A, format='weighted_adjacency_matrix')
sage: HP = hamiltonian_paths(Gamma, signed_adjacency_matrix = A)
sage: L = [sum(x[2]) for x in HP]; max(L)
5
sage: L.index(5)
21
sage: HP[21]
[Graph on 6 vertices,
[0, 5, 2, 1, 3, 4],
[-1, 1, -1, -1, -1, 1, 1, 1, 1, 1, 1, 1, 1, 1, -1]]
sage: L.count(5)
1
"""
ST = Gamma.spanning_trees()
if signed_adjacency_matrix == []:
HP = []
for X in ST:
L = X.degree_sequence()
if max(L)<=2:
#print L,ST.index(X), max(L)
HP.append(X)
return HP
if signed_adjacency_matrix != []:
A = signed_adjacency_matrix
HP = []
for X in ST:
L = X.degree_sequence()
if max(L)<=2:
#VX = X.vertices()
EX = X.edges()
if EX[0][1] != EX[-1][1]:
ranking = X.shortest_path(EX[0][0],EX[-1][1])
else:
ranking = X.shortest_path(EX[0][0],EX[-1][0])
signature = [A[ranking[i]][ranking[j]] for i in range(len(ranking)-1) for j in range(i+1,len(ranking))]
HP.append([X,ranking,signature])
return HP
Wessell describes this method in a different way.
An implementaiton of this in Sagemath/python code is:
def minimum_upset_random(M,N=10):
"""
EXAMPLES:
sage: M = matrix(QQ,[
[0 , 0 , 1 , 0 , 0 , 0 ],
[1, 0 , 0, 1, 1, 0 ],
[0 , 1 , 0 , 1 , 1 , 0 ],
[1 , 0 , 0, 0 , 0 , 0 ],
[1 , 0 , 0 , 1 , 0 , 0 ],
[1 , 1 , 1 , 1 , 1 , 0 ]
])
sage: minimum_upset_random(M)
(
[0 0 1 1 0 1]
[1 0 0 1 0 1]
[0 1 0 0 0 0]
[0 0 1 0 0 0]
[1 1 1 1 0 1]
[0 0 1 1 0 0], [1, 2, 0, 3, 5, 4]
)
"""
n = len(M.rows())
Sn = SymmetricGroup(n)
M1 = M
wins = sum([sum([M1[j][i] for i in range(j,6)]) for j in range(6)])
g0 = Sn(1)
for k in range(N):
g = Sn.random_element()
P = g.matrix()
M0 = P*M1*P^(-1)
if sum([sum([M0[j][i] for i in range(j,6)]) for j in range(6)])>wins:
M1 = M0
g0 = g*g0
return M1,g0(range(n))
A perfect number is a positive integer that is equal to the sum of its proper positive divisors, that is, the sum of its positive divisors excluding the number itself. For example, 1 + 2 + 3 = 6 implies 6 is a perfect number.
Unsolved Problem: Are there any odd perfect numbers?
The belief, by some, that there are none goes back over 500 years (wikipedia).
If you want to check out some recent research into this problem, see oddperfect.org.

(Another unsolved problem: Are there an infinite number of even perfect numbers?)
In 1911, Otto Toeplitz asked the following question.
Inscribed Square Problem: Does every plane simple closed curve contain all four vertices of some square?
This question, also known as the square peg problem or the Toeplitz’ conjecture, is still unsolved in general. (It is known in lots of special cases.)

Inscribed square, by Claudio Rocchini
Thanks to Mark Meyerson (“Equilateral triangles and continuous curves”,Fundamenta Mathematicae, 1980) and others, the analog for triangles is true. For any triangle T and Jordan curve C, there is a triangle similar to T and inscribed in C. (In particular, the triangle can be equilateral.) The survey page by Mark J. Nielsen has more information on this problem.
Added 2016-11-23: See also this recent post by T. Tao.
Added 2020-07-01: This has apparently been solved by Joshua Greene and Andrew Lobb! See their ArXiV paper (https://arxiv.org/abs/2005.09193).
In 1937 Lothar Collatz proposed the 3n+1 conjecture (known by a long list of aliases), is stated as follows.
First, we define the function on the set of positive integers:
If the number is even, divide it by two:
.
If the number is odd, triple it and add one:
.
In modular arithmetic notation, define the function as follows:
, and
. Believe it or not, this is the restriction to the positive integers of the complex-valued map
.
The 3n+1 conjecture is: The sequence
will eventually reach the number 1, regardless of which positive integer is chosen initially.
This is still unsolved, though a lot of people have worked on it. For a recent survey of results, see the paper by Chamberland.
A former colleague Bill Wardlaw (March 3, 1936-January 2, 2013) used to create a “Problem of the Week” for his US Naval Academy students, giving a prize of a cookie if they could solve it. One of them is given below.
The residue of an integer n modulo an integer d > 1 is the remainder r left when n is divided by d. That is, if n = dq + r for integers q and r with 0 < r < d, we write for the residue of n modulo d. Show that the residue modulo 7 of a (large) integer n can be found by separating the integer into 3-digit blocks
.(Note that b(s) may have 1, 2, or 3 digits, but every other block must have exactly three digits.) Then the residue modulo 7 of n is the same as the residue modulo 7 of
. For example,
.
Explain why this works and show that the same trick works for residues modulo 13.
A former colleague Bill Wardlaw (March 3, 1936-January 2, 2013) used to create a “Problem of the Week” for his US Naval Academy students, giving a prize of a cookie if they could solve it. One of them is given below.
Chain addition is a technique employed in cryptography for extending a short sequence of digits, called the seed to a longer sequence of pseudorandom digits. Quoting David Kahn (in Kahn on Codes, MacMillan, New York, 1983, p. 154), “the first two digits of the [seed] are added together modulo 10 [which means they are added and the carry is neglected] and the result placed at the end of the [sequence], then the second and third digits are added and the sum placed at the end, and so forth, using also the newly generated digits when the [seed] is exhausted, until the desired length is obtained”. Thus, the seed 3964 yields the sequence 3964250675632195… .

Periodic pattern
a. Show that this sequence eventually repeats itself.
b. Show that the sequence begins repeating itself with “3964”.
c. EXTRA CREDIT: How many digits are there before the first repetition of “3964”?
A former colleague Bill Wardlaw (March 3, 1936-January 2, 2013) used to create a “Problem of the Week” for his US Naval Academy students, giving a prize of a cookie if they could solve it. One of them is given below.
Suppose p and q are each monic polynomials of degree 4 with real coefficients and the intersection of their graphs is {(1, 3), (5, 21)}. If p(3) – q(3) = 20, what is the area enclosed by their graphs?
A former colleague Bill Wardlaw (March 3, 1936-January 2, 2013) used to create a “Problem of the Week” for his US Naval Academy students, giving a prize of a cookie if they could solve it. One of them is given below.
Let a, b, and c be real numbers and let f and g be real valued functions of a real variable such that and
.
a. Give an example in which .
b. Give an additional condition on f alone and show that it
guarantees .
c. Give an additional condition on g alone and show that it
guarantees .
This post describes some applications of representation theory of non-abelian groups to various fields and gives some references.
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